【Codeforces 631 B Print Check 】+ 简单构造
来源:互联网 发布:红警2mac添加地图 编辑:程序博客网 时间:2024/05/16 04:27
B. Print Check
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
Kris works in a large company “Blake Technologies”. As a best engineer of the company he was assigned a task to develop a printer that will be able to print horizontal and vertical strips. First prototype is already built and Kris wants to tests it. He wants you to implement the program that checks the result of the printing.
Printer works with a rectangular sheet of paper of size n × m. Consider the list as a table consisting of n rows and m columns. Rows are numbered from top to bottom with integers from 1 to n, while columns are numbered from left to right with integers from 1 to m. Initially, all cells are painted in color 0.
Your program has to support two operations:
Paint all cells in row ri in color ai;Paint all cells in column ci in color ai.
If during some operation i there is a cell that have already been painted, the color of this cell also changes to ai.
Your program has to print the resulting table after k operation.
Input
The first line of the input contains three integers n, m and k (1 ≤ n, m ≤ 5000, n·m ≤ 100 000, 1 ≤ k ≤ 100 000) — the dimensions of the sheet and the number of operations, respectively.
Each of the next k lines contains the description of exactly one query:
1 ri ai (1 ≤ ri ≤ n, 1 ≤ ai ≤ 109), means that row ri is painted in color ai;2 ci ai (1 ≤ ci ≤ m, 1 ≤ ai ≤ 109), means that column ci is painted in color ai.
Output
Print n lines containing m integers each — the resulting table after all operations are applied.
Examples
Input
3 3 3
1 1 3
2 2 1
1 2 2
Output
3 1 3
2 2 2
0 1 0
Input
5 3 5
1 1 1
1 3 1
1 5 1
2 1 1
2 3 1
Output
1 1 1
1 0 1
1 1 1
1 0 1
1 1 1
Note
The figure below shows all three operations for the first sample step by step. The cells that were painted on the corresponding step are marked gray.
暴力会超时~更新每个格当前行和列最后一次的数字~输出行和列更新较晚的数字~
AC代码:
#include<cstdio>#include<algorithm>using namespace std;struct node{ int a,b;}st[2][5010];int solve(node x,node y){ if(x.a > y.a) return x.b; else return y.b;}int main(){ int N,M,K; while(scanf("%d %d %d",&N,&M,&K) != EOF){ int nl,x,y; for(int i = 1 ; i <= K; i++){ scanf("%d %d %d",&nl,&x,&y); st[--nl][x].a = i; // 更新每行,每列最后一次的更新时间 st[nl][x].b = y; // 记录最后一次的数字 } for(int i = 1 ; i <= N ;i++){ for(int j = 1 ; j < M; j++) printf("%d ",solve(st[0][i],st[1][j])); // 输出行,列较晚的数字 printf("%d\n",solve(st[0][i],st[1][M])); } } return 0;}
- 【Codeforces 631 B Print Check 】+ 简单构造
- codeforces 631B Print Check
- codeforces 631B Print Check
- CodeForces 631B Print Check
- codeforces 631B Print Check
- Codeforces 631B Print Check 【思维】
- Codeforces 631B Print Check【模拟】
- Codeforces 631 B Print Check【思维】
- codeforces 631B Print Check模拟
- 基础题 CodeForces - 631B Print Check
- CodeForces 631 B.Print Check(水~)
- CodeForces 631B B. Print Check(水题水题)
- codeforces 344 B. Print Check解题报告
- Codeforces Round #344 (Div. 2) B. Print Check【思维】
- Codeforces Round #344 (Div. 2) B. Print Check
- Codeforces Round #344 (Div. 2) B. Print Check (模拟)
- Print Check CodeForces
- codeforces 359B B. Permutation(简单构造)
- kafka客户端
- Action和result之间的PreResultListener监听器
- [Leetcode] Search a 2D Matrix
- php Header文件下载
- 订阅号体验反馈
- 【Codeforces 631 B Print Check 】+ 简单构造
- 创业公司做数据分析(四)ELK日志系统
- 溯源 Uses CGLIB to generate subclasses dynamically if methods need to be overridden by the container
- 欢迎使用CSDN-markdown编辑器
- AAM(Active Appreance Model)主动形状模型通俗易懂讲解
- Codeforces Round #387 (Div. 2) C
- 编程之美(数字的魅力)
- kafka生产者消费者
- [转载]STM32+UCGUI+触摸屏