LeetCode 453. Minimum Moves to Equal Array Elements
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描述
给出一个数组，每次对n - 1个数加1，问经过多少次所有的数相等
解决
对n - 1个数加1等价于对1个数减1，答案就是所有数的和减去数组长度乘以最小数的积
class Solution {public: int minMoves(vector<int>& nums) { int sum = 0, min_val = INT_MAX; for (auto val : nums) { sum += val; if (val < min_val) { min_val = val; } } return sum - nums.size() * min_val; }}; 0 0
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