6. ZigZag Conversion*

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The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   NA P L S I I GY   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

My code:

public class Solution {    public String convert(String s, int numRows) {        char[] c=s.toCharArray();        int len = c.length;        StringBuffer sb = new StringBuffer();        if (numRows==1) return s;        for(int i=0;i<numRows;i++){            int index=i;            int flag=0;            if(i==0||i==numRows-1){                while(index<len){                    sb.append(c[index]);                    index+=2*numRows-2;                }            }            else{                while(index<len){                    sb.append(c[index]);                    if(flag%2==0){                        index+=2*numRows-2-2*i;                    }                    else{                        index+=2*i;                    }                    flag +=1;                                    }            }        }        return sb.toString();    }}

总结：看了答案提示，不过你真棒。这是本来的思路。

public class Solution {    public String convert(String s, int numRows) {        char[] c=s.toCharArray();        int len = c.length;        StringBuffer[] sb = new StringBuffer[numRows];        for(int i=0;i<sb.length;i++){            sb[i] = new StringBuffer();        }        int i=0;        while(i<len){            for(int idx=0;idx<numRows&&i<len;idx++){                sb[idx].append(c[i++]);            }            for(int idx=numRows-2;idx>=1&&i<len;idx--){                sb[idx].append(c[i++]);            }        }        for(int idx=1;idx<sb.length;idx++){            sb[0].append(sb[idx]);        }        return sb[0].toString();    }}

利用list的集合实现遍历，横向每层一个list。

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