使用RestTemplate Spring安全认证

javaspring 认证authentication 安全spring-security
我有提供2个独立的一整套服务2 Spring的web应用程序。 Web应用程序1具有Spring Security的使用认证。 现在，Web应用程序2需要访问Web应用程序1的服务。通常情况下，我们的RestTemplate类来发送请求到其他网络服务。 我们如何通过在Web应用程序2要求的身份验证凭据到Web应用程序1
本文地址 ：CodeGo.net/238843/
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1. 我当时的情况。这里有我的解决方案。 服务器-春季安全配置

<sec:http> <sec:intercept-url pattern="/**" access="ROLE_USER" method="POST"/> <sec:intercept-url pattern="/**" filters="none" method="GET"/> <sec:http-basic /></sec:http><sec:authentication-manager alias="authenticationManager"> <sec:authentication-provider>  <sec:user-service>   <sec:user name="${rest.username}" password="${rest.password}" authorities="ROLE_USER"/>  </sec:user-service> </sec:authentication-provider></sec:authentication-manager>

客户端端RestTemplate配置

<bean id="httpClient" class="org.apache.commons.httpclient.HttpClient"> <constructor-arg ref="httpClientParams"/> <property name="state" ref="httpState"/></bean><bean id="httpState" class="CustomHttpState"> <property name="credentials" ref="credentials"/></bean><bean id="credentials" class="org.apache.commons.httpclient.UsernamePasswordCredentials"> <constructor-arg value="${rest.username}"/> <constructor-arg value="${rest.password}"/></bean><bean id="httpClientFactory" class="org.springframework.http.client.CommonsClientHttpRequestFactory"> <constructor-arg ref="httpClient"/></bean><bean class="org.springframework.web.client.RestTemplate"> <constructor-arg ref="httpClientFactory"/>    </bean>

自定义的HttpState

/** * Custom implementation of {@link HttpState} with credentials property. * * @author banterCZ */public class CustomHttpState extends HttpState { /**  * Set credentials property.  *  * @param credentials  * @see #setCredentials(org.apache.commons.httpclient.auth.AuthScope, org.apache.commons.httpclient.Credentials)  */ public void setCredentials(final Credentials credentials) {  super.setCredentials(AuthScope.ANY, credentials); }}

Maven的依赖

<dependency> <groupId>commons-httpclient</groupId> <artifactId>commons-httpclient</artifactId> <version>3.1</version></dependency>

2. 这里是一个解决方案，它工作得很好，春季3.1和Apache HttpComponents 4.1我创建了这个网站为基础的答案和阅读的springRestTempalte源代码。我在救人的希望分享我觉得spring应该只是有这样的内置代码，但它没有。

RestClient client = new RestClient();client.setApplicationPath("someApp");String url = client.login("theuser", "123456");UserPortfolio portfolio = client.template().getForObject(client.apiUrl("portfolio"),        UserPortfolio.class);

下面是设置了HttpComponents上下文是工厂类上与RestTemplate每个请求。

public class StatefullHttpComponentsClientHttpRequestFactory extends      HttpComponentsClientHttpRequestFactory{ private final HttpContext httpContext; public StatefullHttpComponentsClientHttpRequestFactory(HttpClient httpClient, HttpContext httpContext) {  super(httpClient);  this.httpContext = httpContext; } @Override protected HttpContext createHttpContext(HttpMethod httpMethod, URI uri) {  return this.httpContext; }}

下面是有状态的rest模板，你的cookies，一旦你与它会将JSESSIONID登录并发送它在后续的请求。

public class StatefullRestTemplate extends RestTemplate{ private final HttpClient httpClient; private final CookieStore cookieStore; private final HttpContext httpContext; private final StatefullHttpComponentsClientHttpRequestFactory statefullHttpComponentsClientHttpRequestFactory; public StatefullRestTemplate() {  super();  httpClient = new DefaultHttpClient();  cookieStore = new BasicCookieStore();  httpContext = new BasicHttpContext();  httpContext.setAttribute(ClientContext.COOKIE_STORE, getCookieStore());  statefullHttpComponentsClientHttpRequestFactory = new StatefullHttpComponentsClientHttpRequestFactory(httpClient, httpContext);  super.setRequestFactory(statefullHttpComponentsClientHttpRequestFactory); } public HttpClient getHttpClient() {  return httpClient; } public CookieStore getCookieStore() {  return cookieStore; } public HttpContext getHttpContext() {  return httpContext; } public StatefullHttpComponentsClientHttpRequestFactory getStatefulHttpClientRequestFactory() {  return statefullHttpComponentsClientHttpRequestFactory; }}

这里是一个类来表示一个REST客户端端，让你可以调用抵押和spring有个应用程序安全性。

public class RestClient{ private String host = "localhost"; private String port = "8080"; private String applicationPath; private String apiPath = "api"; private String loginPath = "j_spring_security_check"; private String logoutPath = "logout"; private final String usernameInputFieldName = "j_username"; private final String passwordInputFieldName = "j_password"; private final StatefullRestTemplate template = new StatefullRestTemplate(); /**  * This method logs into a service by doing an standard http using the configuration in this class.  *   * @param username  *   the username to log into the application with  * @param password  *   the password to log into the application with  *   * @return the url that the login redirects to  */ public String login(String username, String password) {  MultiValueMap<String, String> form = new LinkedMultiValueMap<>();  form.add(usernameInputFieldName, username);  form.add(passwordInputFieldName, password);  URI location = this.template.postForLocation(loginUrl(), form);  return location.toString(); } /**  * Logout by doing an http get on the logout url  *   * @return result of the get as ResponseEntity  */ public ResponseEntity<String> logout() {  return this.template.getForEntity(logoutUrl(), String.class); } public String applicationUrl(String relativePath) {  return applicationUrl() + "/" + checkNotNull(relativePath); } public String apiUrl(String relativePath) {  return applicationUrl(apiPath + "/" + checkNotNull(relativePath)); } public StatefullRestTemplate template() {  return template; } public String serverUrl() {  return " CodeGo.net  + host + ":" + port; } public String applicationUrl() {  return serverUrl() + "/" + nullToEmpty(applicationPath); } public String loginUrl() {  return applicationUrl(loginPath); } public String logoutUrl() {  return applicationUrl(logoutPath); } public String apiUrl() {  return applicationUrl(apiPath); } public void setLogoutPath(String logoutPath) {  this.logoutPath = logoutPath; } public String getHost() {  return host; } public void setHost(String host) {  this.host = host; } public String getPort() {  return port; } public void setPort(String port) {  this.port = port; } public String getApplicationPath() {  return applicationPath; } public void setApplicationPath(String contextPath) {  this.applicationPath = contextPath; } public String getApiPath() {  return apiPath; } public void setApiPath(String apiPath) {  this.apiPath = apiPath; } public String getLoginPath() {  return loginPath; } public void setLoginPath(String loginPath) {  this.loginPath = loginPath; } public String getLogoutPath() {  return logoutPath; } @Override public String toString() {  StringBuilder builder = new StringBuilder();  builder.append("RestClient [\n serverUrl()=");  builder.append(serverUrl());  builder.append(", \n applicationUrl()=");  builder.append(applicationUrl());  builder.append(", \n loginUrl()=");  builder.append(loginUrl());  builder.append(", \n logoutUrl()=");  builder.append(logoutUrl());  builder.append(", \n apiUrl()=");  builder.append(apiUrl());  builder.append("\n]");  return builder.toString(); }}

3. 该RestTemplate是非常基本的和有限的 CodeGo.net，似乎没有成为一个简单的方法来做到这一点。最好的办法可能是在Web应用程序1消化基本身份验证的。 Apache的HttpClient的直接从Web应用程序2访问REST服务。 话虽这么说，对于测试我能解决这个一个大劈。基本上，RestTemplate提交登录（j_spring_security_check），解析出JSESSIONID从请求头，然后提交，其余请求。下面的代码，但我怀疑它是为生产做好准备代码的最佳解决方案。

public final class RESTTest { public static void main(String[] args) { RestTemplate rest = new RestTemplate(); HttpsURLConnection.setDefaultHostnameVerifier(new HostnameVerifier() {  @Override  public boolean verify(String s, SSLSession sslsession) {   return true;  } }); // setting up a trust store with JCA is a whole other issue // this assumes you can only log in via SSL // you could turn that off, but not on a production site! System.setProperty("javax.net.ssl.trustStore", "/path/to/cacerts"); System.setProperty("javax.net.ssl.trustStorePassword", "somepassword"); String jsessionid = rest.execute(" CodeGo.net  HttpMethod.POST,   new RequestCallback() {    @Override    public void doWithRequest(ClientHttpRequest request) throws IOException {     request.getBody().write("j_username=user&j_password=user".getBytes());    }   }, new ResponseExtractor<String>() {    @Override    public String extractData(ClientHttpResponse response) throws IOException {     List<String> cookies = response.getHeaders().get("Cookie");     // assuming only one cookie with jsessionid as the only value     if (cookies == null) {      cookies = response.getHeaders().get("Set-Cookie");     }     String cookie = cookies.get(cookies.size() - 1);     int start = cookie.indexOf('=');     int end = cookie.indexOf(';');     return cookie.substring(start + 1, end);    }   }); rest.put(" CodeGo.net  + jsessionid, new DAO("REST Test").asJSON());}

} 注意这个工作，你需要在JCA创建一个存储，以便在SSL连接实际上可以做。我不想让Spring Security的登录是通过纯HTTP的生产现场，因为这将是一个巨大的安全漏洞。
4. 当前凭据应该可以在Web应用程序上1Authentication对象，这是通过访问SecurityContext（例如，你可以通过调用检索SecurityContextHolder.getContext().getAuthentication()）。 当您检索凭据，您将它们访问Web应用程序2。 您可以通过扩展它与decorator（如下所述）通“Authentiation”头与RestTemplateRestTemplate.exchange()方法，如在本论坛发表的文章中描述。
5. 有一个简单的方法来做到这一点的情况下，你是谁在寻找一个简单的调用，而不是一个API

HttpClient client = new HttpClient(); client.getParams().setAuthenticationPreemptive(true); Credentials defaultcreds = new UsernamePasswordCredentials("username", "password"); RestTemplate restTemplate = new RestTemplate(); restTemplate.setRequestFactory(new CommonsClientHttpRequestFactory(client)); client.getState().setCredentials(AuthScope.ANY, defaultcreds);

本文标题 ：使用RestTemplate Spring安全认证
本文地址 ：CodeGo.net/238843/
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