409. Longest Palindrome#2(Done)
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Solution#2
public class Solution { public int longestPalindrome(String s) { if (s == null || s.length() == 0) return 0; int[] lowercase = new int[26]; int[] uppercase = new int[26]; char[] ch = s.toCharArray(); for (char c : ch) { if (c - 'a' >= 0) lowercase[c - 'a']++; else uppercase[c - 'A']++; } int result = 0; for (int i = 0; i < 26; i++) { result += lowercase[i] / 2 * 2; result += uppercase[i] / 2 * 2; } return result == s.length() ? result : result + 1; }}
Solution#1
public class Solution { public int longestPalindrome(String s) { int[] table = new int[52]; for (int i = 0; i < s.length(); i++) { if (s.charAt(i) - 'a' >= 0) { table[26 + s.charAt(i) - 'a']++; } else { table[s.charAt(i) - 'A']++; } } int result = 0; int mid = 0; for (int x : table) { if (x % 2 == 0) result += x; else { if (x > mid) mid = x; } } return result + mid; }}
Problem#1
- 对题目理解不清楚,即使是奇数个也可以抽出偶数个组成回文
- 不用判奇偶减一,可以统一处理
- 效率没有达到最高
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