58. Length of Last Word
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Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = “Hello World”,
return 5.
class Solution {public: int lengthOfLastWord(string s) { int len = 0, sz = s.length(), tmp = 0; for(int i = 0; i < sz; ++i){ if(s[i] == ' ' && tmp != 0){ len = tmp; tmp = 0; } else if(s[i] != ' ') ++tmp; } if(tmp != 0) len = tmp; return len; }};
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- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58.Length of Last Word
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