【qt】gps转百度地图坐标

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作者：lazyboy
邮箱：upc_xbt@163.com
文章同步发布到个人静态博客 www.lazyboy.site

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之前在我的CSDN博客[xbotao2014- gps坐标离线转百度坐标]中已经介绍过如何将gps坐标转换为百度地图坐标，在改博客中提供了C#和java代码的实现。由于功能需要，先转到qt中实现

现CSDN博客已转移到upc_xbt

qt实现gps坐标转百度地图坐标

头文件

#ifndef GPS2BD_H#define GPS2BD_H/* WGS-84：是国际标准，GPS坐标（Google Earth使用、或者GPS模块） GCJ-02：中国坐标偏移标准，Google Map、高德、腾讯使用 BD-09：百度坐标偏移标准，Baidu Map使用代码参考：http://bbs.lbsyun.baidu.com/forum.php?mod=viewthread&tid=10923 */class gps2bd{public:    gps2bd();           static void wgs2gcj(double *result, double lat, double lon);    static void gcj2bd(double *result, double lat, double lon);    static void wgs2bd(double *result, double lat, double lon);    static void bd2gcj(double *result, double lat, double lon);private:    static double transformLon(double lat, double lon);    static double transformLat(double lat, double lon);};#endif // GPS2BD_H

cpp文件

#include "gps2bd.h"#include <QtMath>static double pi = 3.14159265358979324;static double a = 6378245.0;static double ee = 0.00669342162296594323;static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;gps2bd::gps2bd(){}//transformLondouble gps2bd::transformLon(double lat, double lon){    double ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * qSqrt(qFabs(lat));    ret += (20.0 * qSin(6.0 * lat * pi) + 20.0 * qSin(2.0 * lat * pi)) * 2.0 / 3.0;    ret += (20.0 * qSin(lat * pi) + 40.0 * qSin(lat / 3.0 * pi)) * 2.0 / 3.0;    ret += (150.0 * qSin(lat / 12.0 * pi) + 300.0 * qSin(lat / 30.0 * pi)) * 2.0 / 3.0;    return ret;}//transformLatdouble gps2bd::transformLat(double lat, double lon){    double ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * qSqrt(qFabs(lat));    ret += (20.0 * qSin(6.0 * lat * pi) + 20.0 * qSin(2.0 * lat * pi)) * 2.0 / 3.0;    ret += (20.0 * qSin(lon * pi) + 40.0 * qSin(lon / 3.0 * pi)) * 2.0 / 3.0;    ret += (160.0 * qSin(lon / 12.0 * pi) + 320 * qSin(lon * pi / 30.0)) * 2.0 / 3.0;    return ret;}//wgs2gcjvoid gps2bd::wgs2gcj(double *result, double lon, double lat){    double dLat = transformLat(lon - 105.0, lat - 35.0);    double dLon = transformLon(lon - 105.0, lat - 35.0);    double radLat = lat / 180.0 * pi;    double magic = qSin(radLat);    magic = 1 - ee * magic * magic;    double sqrtMagic = qSqrt(magic);    dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);    dLon = (dLon * 180.0) / (a / sqrtMagic * qCos(radLat) * pi);    double mgLat = lat + dLat;    double mgLon = lon + dLon;    result[0] = mgLon;    result[1] = mgLat;}void gps2bd::gcj2bd(double *result, double lon, double lat){    double x = lon, y = lat;    double z = qSqrt(x * x + y * y) + 0.00002 * qSin(y * x_pi);    double theta = qAtan2(y, x) + 0.000003 * qCos(x * x_pi);    double bd_lon = z * qCos(theta) + 0.0065;    double bd_lat = z * qSin(theta) + 0.006;    result[0] = bd_lon;    result[1] = bd_lat;}void gps2bd::wgs2bd(double *result, double lon, double lat){    double gcj[2];    wgs2gcj(gcj, lat, lon);    gcj2bd(result, gcj[0], gcj[1]);}void gps2bd::bd2gcj(double *result, double lon, double lat){    double x = lon - 0.0065, y = lat - 0.006;    double z = qSqrt(x * x + y * y) - 0.00002 * qSin(y * x_pi);    double theta = qAtan2(y, x) - 0.000003 * qCos(x * x_pi);    double gg_lon = z * qCos(theta);    double gg_lat = z * qSin(theta);    result[0] = gg_lon;    result[1] = gg_lat;    //return new double[] { gg_lat, gg_lon };}

使用

//获得经纬度double dLon = ui->lineEdit_lon->text().toDouble();double dLat = ui->lineEdit_lat->text().toDouble();double result[2];gps2bd::wgs2bd(result, dLat, dLon);

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