Leetcode 359 Logger Rate Limiter

Design a logger system that receive stream of messages along with its timestamps, each message should be printed if and only if it is not printed in the last 10 seconds.

Given a message and a timestamp (in seconds granularity), return true if the message should be printed in the given timestamp, otherwise returns false.

It is possible that several messages arrive roughly at the same time.

Example:

Logger logger = new Logger();// logging string "foo" at timestamp 1logger.shouldPrintMessage(1, "foo"); returns true; // logging string "bar" at timestamp 2logger.shouldPrintMessage(2,"bar"); returns true;// logging string "foo" at timestamp 3logger.shouldPrintMessage(3,"foo"); returns false;// logging string "bar" at timestamp 8logger.shouldPrintMessage(8,"bar"); returns false;// logging string "foo" at timestamp 10logger.shouldPrintMessage(10,"foo"); returns false;// logging string "foo" at timestamp 11logger.shouldPrintMessage(11,"foo"); returns true;

这题有点提前设flag的意思。为了判断是否在过去的10s中出现，在每一次print的过程中将未来的10s提前放进map里面。

public class Logger {    /** Initialize your data structure here. */    public Logger() {            }        private Map<String,Integer> time = new HashMap<String,Integer>();    /** Returns true if the message should be printed in the given timestamp, otherwise returns false.        If this method returns false, the message will not be printed.        The timestamp is in seconds granularity. */    public boolean shouldPrintMessage(int timestamp, String message) {        if(timestamp < time.getOrDefault(message,0) )        return false;        time.put(message,timestamp + 10);        return true;    }}/** * Your Logger object will be instantiated and called as such: * Logger obj = new Logger(); * boolean param_1 = obj.shouldPrintMessage(timestamp,message); */