奇怪的web.xml配置错误

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奇怪的web.xml配置错误

为org.springframework.web.servlet.DispatcherServlet设置参数contextConfigLocation自定义spring配置文件的位置，设置完后如下：

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<servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring-servlet.xml</param-value>
    </init-param>
</servlet>

直接部署运行没有问题，但是用eclipse打开就在第5行处报错：

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Description Resource Path Location Type
cvc-complex-type.2.4.a: Invalid content was found starting with element'init-param'.
One of '{"http://java.sun.com/xml/ns/javaee":enabled,"http://java.sun.com/xml/ns/javaee":async-supported,
"http://java.sun.com/xml/ns/javaee":run-as,"http://java.sun.com/xml/ns/javaee":security-role-ref,
"http://java.sun.com/xml/ns/javaee":multipart-config}' is expected.

将配置文件改为：

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<servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring-servlet.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

eclipse就不报怨了，init-param要紧跟servlet-class元素吗？没这规定吧！
是tomcat太宽松了还是eclipse太严格了呢？！

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