485. Max Consecutive Ones \ 118. Pascal's Triangle

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  • Max Consecutive Ones
  • Pascals Triangle

485. Max Consecutive Ones

法一:

class Solution {public:    int findMaxConsecutiveOnes(vector<int>& nums) {        int result_max = 0;        int nums_len = nums.size();        int tmp = 0;        if(!nums_len)            return 0;        else if(nums[0])            {            result_max = 1;        }            for(int i = 0; i < nums_len - 1; i++)        {            if((nums[i] == nums[i + 1]) && nums[i])            {              //  cout << i << " " << tmp << endl;                tmp = (tmp==0)?2:(tmp+1);                if(tmp > result_max)                    result_max = tmp;            }                else             {                if(nums[i] || nums[i+1])                {                    if(!result_max)                        result_max = 1;                }                if(tmp > result_max)                    result_max = tmp;                 tmp = 0;            }        }        return result_max;    }};

法二:

public:    int findMaxConsecutiveOnes(vector<int>& nums) {        int count = 0, max = 0;        for (int i = 0; i < nums.size(); ++i){            if (nums[i]){                if (++count > max) max = count;            }            else count = 0;        }        return max;    }};

118. Pascal’s Triangle

法一:

class Solution {public:    vector<vector<int>> generate(int numRows) {        vector<vector<int> > result;        for(int i = 1; i <= numRows; i++)        {            vector<int> tmp;            for(int j = 1; j <= i; j++)            {                if(j == 1 || j == i)                {                    tmp.push_back(1);                }                if(i > 2 && j>1 && j<i)                {                    tmp.push_back(result[i-2][j-2]+result[i-2][j-1]);                }            }            result.push_back(tmp);        }        return result;    }};

法二:

class Solution {public:    vector<vector<int>> generate(int numRows) {        vector<vector<int>> res;        for(auto i=0;i<numRows;++i)        {            res.push_back(vector<int>(i+1,1));            for(auto j=1; j<i; ++j) res[i][j] = res[i-1][j-1] + res[i-1][j];        }        return res;    }};

在刷题的时候我发现C++的for循环会检查初始条件,C不会。

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