字符串相似度算法( Levenshtein Distance算法)

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/*

字符串相似度算法(Levenshtein Distance算法)

 

一个字符串可以通过增加一个字符,删除一个字符,替换一个字符得到另外一个字符串,假设,我们把从字符串A转换成字符串B,前面种操作所执行的最少次数称为AB相似度

abc adc  度为1

ababababa babababab 度为2

abcd acdb 度为

 

字符串相似度算法可以使用Levenshtein Distance算法(中文翻译:编辑距离算法) 这算法是由俄国科学家Levenshtein提出的。

 

Step Description

 

1   Set n to be the length of s.

    Set m to be the length of t.

    If n = 0, return m and exit.

    If m = 0, return n and exit.

    Construct a matrix containing 0..m rows and 0..n columns. 

2    Initialize the first row to 0..n.

    Initialize the first column to 0..m.

 

3   Examine each character of s (i from 1 to n).

4   Examine each character of t (j from 1 to m).

5   If s[i] equals t[j], the cost is 0.

    If s[i] doesn't equal t[j], the cost is 1.

6   Set cell d[i,j] of the matrix equal to the minimum of:

    a. The cell immediately above plus 1: d[i-1,j] + 1.

    b. The cell immediately to the left plus 1: d[i,j-1] + 1.

    c. The cell diagonally above and to the left plus the cost: d[i-1,j-1] + cost.

 

7   After the iteration steps (3, 4, 5, 6) are complete, the distance is found in cell d[n,m].

 

*/

 

 

#include <iostream>

#include <vector>

#include <string>

using namespace std;

 

//算法

int ldistance(const string source,const string target)

{

    //step 1

 

    int n=source.length();

    int m=target.length();

    if (m==0) return n;

    if (n==0) return m;

    //Construct a matrix

    typedef vector< vector<int> >  Tmatrix;

    Tmatrix matrix(n+1);

    for(int i=0; i<=n; i++)  matrix[i].resize(m+1);

 

    //step 2 Initialize

 

    for(int i=1;i<=n;i++) matrix[i][0]=i;

    for(int i=1;i<=m;i++) matrix[0][i]=i;

 

    //step 3

    for(int i=1;i<=n;i++)

    {

        const char si=source[i-1];

        //step 4

        for(int j=1;j<=m;j++)

        {

 

            const char dj=target[j-1];

            //step 5

            int cost;

            if(si==dj){

                cost=0;

            }

            else{

                cost=1;

            }

            //step 6

            const int above=matrix[i-1][j]+1;

            const int left=matrix[i][j-1]+1;

            const int diag=matrix[i-1][j-1]+cost;

            matrix[i][j]=min(above,min(left,diag));

 

        }

    }//step7

    return matrix[n][m];

}

int main(){

    string s;

    string d;

    cout<<"source=";

    cin>>s;

    cout<<"diag=";

    cin>>d;

    int dist=ldistance(s,d);

    cout<<"dist="<<dist<<endl;

}

 

原文:

http://www.cppblog.com/whncpp/archive/2008/09/21/62378.html

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