UVa1587 - Box

//UVa1587 - Box//题目：给出6个矩形的长和宽，判断它们能否构成长方体的六个面//6/3=2 个相同的面 WA,no more data in#include <stdio.h>#include<algorithm>using namespace std;int x[6],y[6],z[6];bool right(void){sort(z,z+6);for(int i=0; i<6; i+=2) if(z[i] != z[i+1])return false;return true;}int main(){while(scanf("%d%d%d%d%d%d%d%d%d%d%d%d",&x[0],&y[0],&x[1],&y[1],&x[2],&y[2],&x[3],&y[3],&x[4],&y[4],&x[5],&y[5]) == 12){int is = 0;for(int i = 0; i < 6; i++) {if(x[i] < y[i]) swap(x[i], y[i]);else if(x[i] == y[i])is++;z[i]= x[i]*y[i]+2*1314;//纯C写法,用z[i]构造加密}if(!is)printf("%s\n", right() ? "POSSIBLE" : "IMPOSSIBLE");else if(is >= 2)printf("IMPOSSIBLE\n");}return 0;}