1027. Colors in Mars (20)

1. 原题： https://www.patest.cn/contests/pat-a-practise/1027

2. 思路：

题意：
10进制转成13进制.
比较简单，直接转换就好。

3. 源码（已AC）：

#include<iostream>using namespace std;char base[13] = {'0', '1', '2', '3', '4', '5','6', '7', '8', '9', 'A', 'B', 'C'};void Convert(int x, char *y);//函数，转换成13进制int main(){freopen("in.txt", "r", stdin);int r, g, b;cin >> r >> g >> b;char r2[3], g2[3], b2[3];Convert(r, r2);Convert(g, g2);Convert(b, b2);cout <<"#" << r2 << g2 << b2 << endl;return 0;}void Convert(int x, char *y){y[0] = base[x/13];y[1] = base[x%13];y[2] = '\0';//注意字符串结束要加结束符}