HDU-1331 Function Run Fun （记忆化搜索）

最简单的记忆化搜索，题目有点问题，a, b, c中若既满足其中一个不大于0，又满足其中一个大于20，按前一种情况。

Code:

#include<bits/stdc++.h>using namespace std;int w[21][21][21];int dfs(int a, int b, int c) {    if (a <= 0 || b <= 0 || c <= 0) return 1;    if (~w[a][b][c]) return w[a][b][c];     if (a < b && b < c) return w[a][b][c] = dfs(a, b, c-1) + dfs(a, b-1, c-1) - dfs(a, b-1, c);    else return w[a][b][c] = dfs(a-1, b, c) + dfs(a-1, b-1, c) + dfs(a-1, b, c-1) - dfs(a-1, b-1, c-1);}int main() {    int a, b, c, ans;    memset(w, -1, sizeof(w));    while(~scanf("%d%d%d", &a, &b, &c)) {        if (a == -1 && b == -1 && c == -1) break;        if (a <= 0 || b <= 0 || c <= 0) ans = 1;        else if (a > 20 || b > 20 || c > 20) ans = dfs(20, 20, 20);        else ans = dfs(a, b, c);        printf("w(%d, %d, %d) = %d\n", a, b, c, ans);    }    return 0;}