E - Y2K Accounting Bug 题解



Accounting for Computer Machinists (ACM) has sufferred from the Y2K bug and lost some vital data for preparing annual report for MS Inc.
All what they remember is that MS Inc. posted a surplus or a deficit each month of 1999 and each month when MS Inc. posted surplus, the amount of surplus was s and each month when MS Inc. posted deficit, the deficit was d. They do not remember which or how many months posted surplus or deficit. MS Inc., unlike other companies, posts their earnings for each consecutive 5 months during a year. ACM knows that each of these 8 postings reported a deficit but they do not know how much. The chief accountant is almost sure that MS Inc. was about to post surplus for the entire year of 1999. Almost but not quite.

Write a program, which decides whether MS Inc. suffered a deficit during 1999, or if a surplus for 1999 was possible, what is the maximum amount of surplus that they can post.

Input

Input is a sequence of lines, each containing two positive integers s and d.

Output

For each line of input, output one line containing either a single integer giving the amount of surplus for the entire year, or output Deficit if it is impossible.

Sample Input

59 237375 743200000 8496942500000 8000000

Sample Output

11628300612Deficit

题意：每五个月报一次表，这个表一定是亏得，这五个月为1-5,2-6,3-7.......然后你输入是s和d，s代表的是每月盈利，d代表每月亏损，问你每年最大能赚多少钱。

分6种情况：（x为这五个月中盈利月的个数）1.当x为1时ssssd，ssssd，ss。x为2sssdd，sssdd，ss。x为3ssddd，ssddd，ss。x为4sdddd，sdddd，sd。x为5ddddd，ddddd，dd这时一定亏损，so代码如下：

#include <iostream>using namespace std;

int main(){ int s,d; int res; while(cin>>s && cin>>d) {  if(d>4*s)res=10*s-2*d;  else if(2*d>3*s)res=8*s-4*d;  else if(3*d>2*s)res=6*(s-d);  else if(4*d>s)res=3*(s-3*d);  else res=-1;  if(res<0)cout<<"Deficit"<<endl;  else cout<<res<<endl; } return 0;}