347. Top K Frequent Elements

Given a non-empty array of integers, return the k most frequent elements.

For example,

• Given [1,1,1,2,2,3] and k = 2, return [1,2].

Note:

• You may assume k is always valid, 1 ≤ k ≤ number of unique elements.
• Your algorithm’s time complexity must be better than O(n log n), where n is the array’s size.

使用unordered_map和priority_queue，时间复杂度O(n*lg(n-k))。

class Solution {public:    vector<int> topKFrequent(vector<int>& nums, int k) {        unordered_map<int, int> ump;        for(auto num : nums)            ump[num]++;        vector<int> res;        priority_queue<pair<int, int>> pq;        for(auto it : ump){            pq.push(make_pair(it.second, it.first));  //pair<first, second>, in priority_queue ths first is frequency, second is number            if(pq.size() > ump.size() - k){                res.push_back(pq.top().second);                pq.pop();            }        }        return res;    }};