【Leetcode】237. Delete Node in a Linked List
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思路:
从链表中,删除指定的节点,但又没有给出前指针。将当前结点伪装成下一个结点,然后将下一个结点删除即可。
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */public class Solution { public void deleteNode(ListNode node) { node.val = node.next.val; node.next = node.next.next; }}
Runtime:1ms
1 0
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