LeetCode Jump Game

来源:互联网 发布:程序员压力大吗 编辑:程序博客网 时间:2024/06/18 00:21

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

For example:
A = [2,3,1,1,4], return true.

A = [3,2,1,0,4], return false.


代码如下:

class Solution {public:    bool canJump(vector<int>& nums)          {              if(nums.size() < 2)                  return true;                            int pos=0,currentMax=0,nextMax=0;              while(currentMax-pos+1 >0)            {                for(;pos<=currentMax;pos++)                {                    if(pos+nums[pos] > nextMax)                        nextMax = pos+nums[pos];                    if(nextMax >= nums.size()-1)                        return true;                }                currentMax = nextMax;            }            return false;      }  };


0 0
原创粉丝点击