Codeforces Round #396(Div. 2)A. Mahmoud and Longest Uncommon Subsequence【水题】

A. Mahmoud and Longest Uncommon Subsequence

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.

Given two strings a and b, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence of one of them and not a subsequence of the other.

A subsequence of some string is a sequence of characters that appears in the same order in the string, The appearances don't have to be consecutive, for example, strings "ac", "bc", "abc" and "a" are subsequences of string "abc" while strings "abbc" and "acb" are not. The empty string is a subsequence of any string. Any string is a subsequence of itself.

Input

The first line contains string a, and the second line — stringb. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than10⁵ characters.

Output

If there's no uncommon subsequence, print "-1". Otherwise print the length of the longest uncommon subsequence ofa and b.

Examples

Input

abcddefgh

Output

5

Input

aa

Output

-1

Note

In the first example: you can choose "defgh" from stringb as it is the longest subsequence of stringb that doesn't appear as a subsequence of stringa.

题目大意：

找两个字符串的最长不公共子串。

思路：

两个字符串的最长布公公子串就应该是其中一个字符串本身，那么判断两个字符串是否相等，如果相等，那么肯定没有公共子串，结果就是-1.否则就是两个字符串中长的那个的长度。

Ac代码：

#include<stdio.h>#include<string.h>#include<iostream>using namespace std;char a[100005];char b[100005];int main(){    while(~scanf("%s%s",a,b))    {        if(strcmp(a,b)==0)printf("-1\n");        else printf("%d\n",max(strlen(a),strlen(b)));    }}