PAT:A1082. Read Number in Chinese (0/25)

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu". Note: zero ("ling") must be handled correctly according to the Chinese tradition. For example, 100800 is "yi Shi Wan ling ba Bai".

Input Specification:

Each input file contains one test case, which gives an integer with no more than 9 digits.

Output Specification:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

Sample Input 1:

-123456789

Sample Output 1:

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

Sample Input 2:

100800

Sample Output 2:

yi Shi Wan ling ba Bai

#include <cstdio>#include <cstring>char num[10][5]={    "ling","yi","er","san","si","wu","liu","qi","ba","jiu"};char wei[5][5]={    "Shi","Bai","Qian","Wan","Yi"};int main(){    char str[15];    gets(str);    int len=strlen(str);    int left=0,right=len-1;    if(str[0]=='-'){        printf("Fu");        left++;    }    while(left+4<=right){        right-=4;    }    while(left<len){        bool flag=false;        bool isPrint=false;        while(left<=right){            if(left>0&&str[left]=='0'){                flag=true;            }else{                if(flag==true){                    printf(" ling");                    flag=false;                }                if(left>0)printf(" ");                printf("%s",num[str[left]-'0']);                isPrint=true;                if(left!=right){                    printf(" %s",wei[right-left-1]);                }            }            left++;        }        if(isPrint==true&&right!=len-1){            printf(" %s",wei[(len-1-right)/4+2]);        }        right+=4;    }    return 0;}