配置SpringMVC的<init-param>标签时的错误cvc-complex-type.2.4.a

配置web.xml中dispatcherServlet的初始化上下文路径时，出现如下错误：

配置文件信息如下：

[html] view plain copy

 

1. <!--配置分发器DispatcherServlet -->  
2. <servlet>  
3.     <servlet-name>dispatcherContext</servlet-name>  
4.     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>  
5.     <load-on-startup>1</load-on-startup></span>  
6.     <init-param><!--这里出现报错信息-->  
7.         <param-name>contextConfigLocationServlet</param-name>  
8.         <param-value>/xxxxxxxxx/dispatcherContext-servlet.xml</param-value>  
9.     </init-param></span>  
10. </servlet>  
11. <servlet-mapping>  
12.     <servlet-name>dispatcherContext</servlet-name>  
13.     <url-pattern>/</url-pattern>  
14. </servlet-mapping>  

将<init-param></init-param>标签对和<load-on-startup></load-on-startup>标签对顺序调换一下就可以了：

[html] view plain copy

 

1. <servlet>  
2.     <servlet-name>dispatcherContext</servlet-name>  
3.     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>  
4.     <init-param>  
5.         <param-name>contextConfigLocationServlet</param-name>  
6.         <param-value>/xxxxxxxx/dispatcherContext-servlet.xml</param-value>  
7.     </init-param></span>  
8. <load-on-startup>1</load-on-startup></span>  
9. </servlet>  
10. <servlet-mapping>  
11.     <servlet-name>dispatcherContext</servlet-name>  
12.     <url-pattern>/</url-pattern>  
13. </servlet-mapping>