|Hdu 1542|线段树|Atlantis
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Hdu传送门
线段树离散化以后进行扫描线。
http://www.cnblogs.com/scau20110726/archive/2013/03/21/2972808.html
这篇文章讲得很好,详解看以上网站
#include<cstdio> #include<algorithm> #include<cstring> #include<vector>#define ms(i,j) memset(i,j, sizeof i);using namespace std;const int MAXN = 100 + 5;struct xian{ int f; //up or down, up is -1, down is 1 double l, r;//the interval's end points double h;//height bool operator < (const xian &b) const { return h<b.h; }}a[MAXN*2];double hashs[MAXN*2];//the hashsed pointsint n; #define lc o*2#define rc o*2+1#define M (l+r)/2struct st{ int col[MAXN*4*4];//col[i]>0 means this inerval was full marked double sum[MAXN*4*4];//available room void pushup(int o, int l, int r) { if (col[o]>0) { sum[o] = hashs[r+1]-hashs[l]; } else if (l==r) sum[o] = 0; else { sum[o] = sum[lc] + sum[rc]; } } void update(int o, int l ,int r, int x, int y, int c) { if (x<=l&&r<=y) { col[o] += c; pushup(o,l,r); return ; } if (x<=M) update(lc,l,M,x,y,c); if (M<y) update(rc,M+1,r,x,y,c); pushup(o,l,r); }}tree;//binary-search the elements in hashs[]int find(int x, int y, double v){ int l = x, r = y, mid; while (l<r) { mid = (l+r)/2; if (v>hashs[mid]) { l = mid+1; } else r = mid; } return r;}int main() { int kase = 0; while (scanf("%d", &n)==1&&n) { kase++; for (int i=0;i<n;i++) { double x1, y1, x2, y2; scanf("%lf%lf%lf%lf", &x1,&y1,&x2,&y2); a[i*2].f = 1; a[i*2+1].f = -1; a[i*2].l = x1; a[i*2+1].l = x1; a[i*2].r = x2; a[i*2+1].r = x2; a[i*2].h = y1; a[i*2+1].h = y2;//add xian hashs[i*2] = x1; hashs[i*2+1] = x2;//add hashs } sort(hashs, hashs+2*n); sort(a, a+2*n); //sort to hashs //delete the repeated elements int m = 1; for (int i=1;i<2*n;i++) if (hashs[i]!=hashs[i-1]) hashs[m++] = hashs[i]; //produce ms(tree.col, 0); double ans = 0; for (int i=0;i<n*2;i++) { int l = find(0, m, a[i].l); int r = find(0, m, a[i].r)-1; /*int l = lower_bound(hashs, hashs+m, a[i].l)-hashs; int r = lower_bound(hashs, hashs+m, a[i].r)-hashs-1;*/ if (r>=l) tree.update(1,0,m-2,l,r,a[i].f);//一定要r>=l,这里原来错了 ans += (a[i+1].h-a[i].h)*tree.sum[1]; } printf("Test case #%d\nTotal explored area: %.2f\n\n", kase, ans); } return 0; }
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