423. Reconstruct Original Digits from English

public class Solution {    public String originalDigits(String s) {        int[] count = new int[10];        for (int i = 0; i < s.length(); i++){            char c = s.charAt(i);            if (c == 'z') count[0]++;            if (c == 'w') count[2]++;            if (c == 'x') count[6]++;            if (c == 's') count[7]++; //7-6            if (c == 'g') count[8]++;            if (c == 'u') count[4]++;             if (c == 'f') count[5]++; //5-4            if (c == 'h') count[3]++; //3-8            if (c == 'i') count[9]++; //9-8-5-6            if (c == 'o') count[1]++; //1-0-2-4        }        count[7]-=count[6];        count[5]-=count[4];        count[3]-=count[8];        count[9]=count[9]-count[8]-count[5]-count[6];        count[1]=count[1]-count[0]-count[2]-count[4];        StringBuilder sb=new StringBuilder();        for(int i=0;i<10;i++){          for(int j=0;j<count[i];j++)              sb.append(i);        }        return sb.toString();    }}