Map<String,Object> ,List 顺序排列

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1.List<Integer> 顺序排列

List<String> list = new ArrayList<>();list.add("a");list.add("c");list.add("b");list.add("e");//通过Collections.sort(List I,Comparator c)方法进行排序Collections.sort(list, new Comparator<String>() {    @Override    public int compare(String o1, String o2) {        return o2.compareTo(o1);    }});for (String s : list) {    System.out.println(s);}

2.Map<String,Integer> 按照value 排序

Map<String, Integer> map_Data = new TreeMap<>();map_Data.put("A", 98);map_Data.put("D", 50);map_Data.put("F", 76);map_Data.put("B", 23);map_Data.put("E", 85);map_Data.put("C", 50);System.out.println(map_Data);//将Map转化为List集合，List采用ArrayListList<Map.Entry<String, Integer>> list_Data = new ArrayList<>(map_Data.entrySet());//通过Collections.sort(List I,Comparator c)方法进行排序Collections.sort(list_Data,new Comparator<Map.Entry<String, Integer>>() {    @Override    public int compare(Map.Entry<String, Integer> o1, Map.Entry<String, Integer> o2) {        return (o1.getValue().compareTo(o2.getValue()));    }});System.out.println(list_Data);

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