Python发送http请求解析返回json小demo

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python发起http请求,并解析返回的json字符串的小demo,方便以后用到。

    #! /usr/bin/env python    # -*- coding:gbk -*-    import os    import sys    import json    import urllib    import urllib2    if __name__ == "__main__":        query_file = sys.argv[1]        query_index = 0        with open(query_file, 'r') as fp:            for line in fp:                query = line.rstrip()                query_index = query_index + 1                query_gbk = query                query = query.decode('gbk', 'ignore').encode('utf8', 'ignore')                url = 'http://10.42.141.12:8089/adrender?query=%s&ad_num=3&srcid=101'\\                      '&ip=172.22.182.55&baiduid=61ABB404320C72436EB6B8352DFBB388:FG=1' % (query)                req = urllib2.urlopen(url)                page = req.read()                ddict = json.loads(page)                expid = ddict['expid']                sid = ddict['sid']                ad_num = ddict['response_adnum']                for i in range(0, ad_num):                    output_html = '%s-%d.html' % (query_gbk, i)                    output = open(output_html, 'w')                    ad = ddict['response_ads'][i].encode('utf8', 'ignore')                    output.write('<html>\')                    output.write('<head>\    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">\<head>\')                    output.write("%s" % (ad))                    output.write('\</html>\')                    output.close()

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