JS截取URL中参数值

来源:互联网 发布:2016全国各地上牌数据 编辑:程序博客网 时间:2024/06/04 23:31

实现方法

function getParamStr(){            //获取url            var url = location.search;                var theRequest = new Object();               //获取url中"?"符后的字串               if (url.indexOf("?") != -1) {                   var str = url.substr(1);                  strs = str.split("&");                  for(var i = 0; i < strs.length; i ++) {                      theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);                  }               }               return theRequest;        }

调用

var Request = new Object();Request = getParamStr();var orderId;//获取url中orderId参数值orderId = Request['orderId'];
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