HDU1258 Sum It Up (DFS)
来源:互联网 发布:cs online mac 编辑:程序博客网 时间:2024/05/18 13:30
Sum It Up
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6429 Accepted Submission(s): 3350
Problem Description
Given a specified total t and a list of n integers, find all distinct sums using numbers from the list that add up to t. For example, if t=4, n=6, and the list is [4,3,2,2,1,1], then there are four different sums that equal 4: 4,3+1,2+2, and 2+1+1.(A number can be used within a sum as many times as it appears in the list, and a single number counts as a sum.) Your job is to solve this problem in general.
Input
The input will contain one or more test cases, one per line. Each test case contains t, the total, followed by n, the number of integers in the list, followed by n integers x1,...,xn. If n=0 it signals the end of the input; otherwise, t will be a positive integer less than 1000, n will be an integer between 1 and 12(inclusive), and x1,...,xn will be positive integers less than 100. All numbers will be separated by exactly one space. The numbers in each list appear in nonincreasing order, and there may be repetitions.
Output
For each test case, first output a line containing 'Sums of', the total, and a colon. Then output each sum, one per line; if there are no sums, output the line 'NONE'. The numbers within each sum must appear in nonincreasing order. A number may be repeated in the sum as many times as it was repeated in the original list. The sums themselves must be sorted in decreasing order based on the numbers appearing in the sum. In other words, the sums must be sorted by their first number; sums with the same first number must be sorted by their second number; sums with the same first two numbers must be sorted by their third number; and so on. Within each test case, all sums must be distince; the same sum connot appear twice.
Sample Input
4 6 4 3 2 2 1 15 3 2 1 1400 12 50 50 50 50 50 50 25 25 25 25 25 250 0
Sample Output
Sums of 4:43+12+22+1+1Sums of 5:NONESums of 400:50+50+50+50+50+50+25+25+25+2550+50+50+50+50+25+25+25+25+25+25
Source
浙江工业大学第四届大学生程序设计竞赛
不知道为什么原先用%s输出时有时会输出abc而不是数字,无奈只好调整为%d输出,然后就AC了。
#include <cstdio>#include <cstring>using namespace std;int t,n,a[105];char b[1005][105],c[105],cnt;void dfs(int k, int cur, int m){ if(cur == t){ c[m] = '\0'; int i; for(i = 0; i < cnt; i ++){ if(!strcmp(b[i],c)) break; } if(i == cnt){ strcpy(b[cnt],c); cnt++; } return; } for(int i = k; i < n; i ++){ if(cur + a[i] <= t){ c[m] = a[i] + '0'; dfs(i+1,cur+a[i],m+1); } }}int main(){ while(~scanf("%d%d",&t,&n) && n){ int sum = 0; for(int i = 0; i < n; i ++){ scanf("%d",&a[i]); sum += a[i]; } if(sum < t){ printf("Sums of %d:\n",t); printf("NONE\n"); continue; } cnt = 0; printf("Sums of %d:\n",t); dfs(0,0,0); if(!cnt) printf("NONE\n"); else for(int i = 0; i < cnt; i ++){ int j = 0; while(b[i][j] != '\0'){ if(!j) printf("%d",b[i][j] - 48); else{ printf("+"); printf("%d",b[i][j] - 48); } j ++; } printf("\n"); } } return 0;}
0 0
- hdu1258 Sum It Up(dfs)
- HDU1258 Sum It Up(DFS)
- HDU1258 Sum It Up (DFS)
- HDU1258:Sum It Up(DFS)
- hdu1258 Sum It Up (DFS)
- Sum It Up(hdu1258,dfs)
- HDU1258:Sum It Up(DFS)
- HDU1258:Sum It Up(DFS)
- DFS hdu1258 Sum It Up
- HDU1258 Sum It Up(DFS)
- hdu1258(Sum It Up)
- HDU1258 Sum It Up 【DFS】+【判重】
- HDU1258 POJ1564 Sum It Up DFS
- HDU1258 Sum It Up
- HDU1258:Sum It Up
- Sum It Up hdu1258
- HDU1258 Sum it up
- HDU1258 Sum It Up
- 策略模式学习1
- 设计模式六大原则
- 通过 Chrome 调试运行在 IOS-safari 上的页面
- ubuntu 16.04 使用virt-manager 安装win7 虚拟机
- QT打包
- HDU1258 Sum It Up (DFS)
- 系统架构相关文章
- 在mac上配置sublime text3时No such file or directory或者Operation not permitted
- codeforces 767C Garland 【dfs】
- javascript textarea的换行符
- python基础语法——循环(二)
- 【树莓派】添加rtl8192eu无线网卡驱动
- elasticsearch中的字段类型/mapping参数
- 系统级性能分析工具 — Perf