LeetCode:Sum of Two Integers
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//特别注意,这一题是关于位运算的典型问题
思想是分别处理相同位和不同位的二进制数,使用& 和 ^两个操作
&得到的结果是除以2后得到
^得到的则无需处理
Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -.
Example:
Given a = 1 and b = 2, return 3.
class Solution {public: int getSum(int a, int b) { if(b==0) return a; int sum,carry; sum = a^b; carry = (a&b)<<1; return getSum(sum,carry); }};
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