242. Valid Anagram

trival，排序后比较

class Solution {public:    static bool cmp(char& c1, char& c2)    {        if(c1<c2)            return true;        else            return false;    }    bool isAnagram(string s, string t) {        sort(s.begin(),s.end(),cmp);        sort(t.begin(),t.end(),cmp);        //cout<<s<<" "<<t<<endl;        if(s.size()!=t.size())            return false;        else        {            for(int i=0;i<s.size();i++)            {                if(s[i]!=t[i])                    return false;            }            return true;        }    }};