【Leetcode】530. Minimum Absolute Difference in BST

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思路:

(1)先序遍历二叉树,得到的遍历结果存入List;

(2)对List进行排序,遍历List,依次判断每相邻两个值的差是否小于最小值result,是则更新result。

/** * Definition for a binary tree node. * public class TreeNode { *     int val; *     TreeNode left; *     TreeNode right; *     TreeNode(int x) { val = x; } * } */public class Solution {    List<Integer> nodes = new ArrayList<Integer>();     public int getMinimumDifference(TreeNode root) {        triversal(root);        Collections.sort(nodes);        int result = Integer.MAX_VALUE;        for (int i = 1; i < nodes.size(); i++) {            if (nodes.get(i) - nodes.get(i - 1) < result)                result = nodes.get(i) - nodes.get(i - 1);        }        return result;    }    public void triversal(TreeNode root) {        if (root != null) {            nodes.add(root.val);            triversal(root.left);            triversal(root.right);        }    }}

Runtime:26ms

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