leetcode495 Teemo Attacking Java
来源:互联网 发布:java 遍历string数组 编辑:程序博客网 时间:2024/06/01 07:26
In LLP world, there is a hero called Teemo and his attacking can make his enemy Ashe be in poisoned condition. Now, given the Teemo's attacking ascending time series towards Ashe and the poisoning time duration per Teemo's attacking, you need to output the total time that Ashe is in poisoned condition.
You may assume that Teemo attacks at the very beginning of a specific time point, and makes Ashe be in poisoned condition immediately.
Example 1:
Input: [1,4], 2Output: 4Explanation: At time point 1, Teemo starts attacking Ashe and makes Ashe be poisoned immediately.
This poisoned status will last 2 seconds until the end of time point 2.
And at time point 4, Teemo attacks Ashe again, and causes Ashe to be in poisoned status for another 2 seconds.
So you finally need to output 4.
Example 2:
Input: [1,2], 2Output: 3Explanation: At time point 1, Teemo starts attacking Ashe and makes Ashe be poisoned.
This poisoned status will last 2 seconds until the end of time point 2.
However, at the beginning of time point 2, Teemo attacks Ashe again who is already in poisoned status.
Since the poisoned status won't add up together, though the second poisoning attack will still work at time point 2, it will stop at the end of time point 3.
So you finally need to output 3.
Note:
- You may assume the length of given time series array won't exceed 10000.
- You may assume the numbers in the Teemo's attacking time series and his poisoning time duration per attacking are non-negative integers, which won't exceed 10,000,000.
思路就是先算出每次中毒不冲突的总时间,再把之间冲突的时间给减去。
public int findPoisonedDuration(int[] timeSeries, int duration) {int result = timeSeries.length * duration;for(int i=1; i<timeSeries.length; i++) {if(timeSeries[i] - timeSeries[i-1] < duration) {result -= duration - (timeSeries[i] - timeSeries[i-1]);}}return result;}
0 0
- leetcode495 Teemo Attacking Java
- 495. Teemo Attacking(Java)
- Leetcode495 Teemo Attacting
- Teemo Attacking
- Teemo Attacking
- Teemo Attacking
- LeetCode题解:Teemo Attacking
- 495. Teemo Attacking
- LeetCode 495. Teemo Attacking
- LeetCode: Teemo Attacking
- LeetCode 495. Teemo Attacking
- LeetCode 495 --- Teemo Attacking
- 495. Teemo Attacking
- 495. Teemo Attacking
- 495. Teemo Attacking
- LeetCode:495. Teemo Attacking
- 【Leetcode】495. Teemo Attacking
- 495. Teemo Attacking
- What is a callback api
- 单链表之快速排序
- Eclipse新建工程(或导入已有工程)工程文件夹内各文件用途
- dao层 service层 action层
- css样式的使用(二)-选择器(上)
- leetcode495 Teemo Attacking Java
- AT&T
- 驱动模块Makefile解析
- 业界 | 中国人工智能黄金时代
- React Native打包
- 优雅显示apache报错页面
- c++ 模板类不能分离接口与实现
- 配置redis外网可访问
- 软件测试的“教”程