LeetCode-190. Reverse Bits
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问题：https://leetcode.com/problems/reverse-bits/?tab=Description
Reverse bits of a given 32 bits unsigned integer.把二进制数翻转。
For example, given input 43261596
(represented in binary as 0000010100101000001111010011100),
return 964176192 (represented in binary as 00111001011110000010100101000000).
分析：先取得n的最后一位，再右移一位，将结果的res左移一位，与n最后一位与。
参考C++代码：
class Solution {public: uint32_t reverseBits(uint32_t n) { int res=0; for(int i=0;i<32;i++){ int tem=n&1; n=n>>1; res=(res<<1) | tem; } return res; }}; 0 0
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