492. Construct the Rectangle

For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4Output: [2, 2]Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:

1. The given area won't exceed 10,000,000 and is a positive integer
2. The web page's width and length you designed must be positive integers.

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所求最小偏差的m,l值，所以从area开平方根的地方开始向两边扩展来算。

public int[] constructRectangle(int area) {       int[] re={0,0};   int result= (int) Math.sqrt(area);       if(result*result==area){       re[0]=re[1]=result;       }else {       for (int i = result; i < area+1; i++) {       int m=area/i;       if(m*i==area){       if (m>i) {       re[0]=m;re[1]=i;       }else {re[0]=i;re[1]=m;       }       break;       }}}       return re;    }