LeetCode : Valid Anagram
来源:互联网 发布:网络骗女性的骗术大全 编辑:程序博客网 时间:2024/06/05 18:17
Given two strings s and t, write a function to determine if t is an anagram of s.
For example,
s = “anagram”, t = “nagaram”, return true.
s = “rat”, t = “car”, return false.
Note:
You may assume the string contains only lowercase alphabets.
Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?
class Solution {public: bool isAnagram(string s, string t) { if(s.length()==0&&t.length()==0) return true; sort(s.begin(),s.end()); sort(t.begin(),t.end()); if(s.compare(t)==0) return true; else return false; }};
0 0
- Leetcode #242 Valid Anagram
- leetcode-242-Valid Anagram
- Leetcode: Valid Anagram
- 【leetCode】Valid Anagram
- [leetcode] 242.Valid Anagram
- leetcode 242: Valid Anagram
- 【leetcode】Valid Anagram
- [leetcode] Valid Anagram
- LeetCode Valid Anagram
- 【LeetCode】242 Valid Anagram
- [LeetCode] Valid Anagram
- leetcode: Valid Anagram
- leetCode(53):Valid Anagram
- leetcode Valid Anagram 异位体
- [leetcode 242]Valid Anagram
- leetcode Valid Anagram
- leetCode #242 Valid Anagram
- LeetCode题解:Valid Anagram
- linux 上使用ftp上传文件
- 快速幂取模(分治思想)
- 设计模式之装饰者模式
- 安卓测试apk中,解决手机安卓不了应用的问题
- UVa 253
- LeetCode : Valid Anagram
- spring roo 开发meavn项目(六)文件夹及子文件夹下载
- 九度OJ-1186:打印日期
- 仿伙伴云表格的筛选控件
- Bootstrap学习-网格系统
- 数据库语句 英文中意
- webstorm 2016(2016.11.25更新)11 12 (注册,激活,破解,码,一起支持正版,最新可用)
- unity接入咪咕SDK遇到的坑
- jstack分析