485 Max Consecutive Ones

485 Max Consecutive Ones
求连续的1的个数
第一个想到的老办法，用两个指针：start来记录开始与结束

class Solution(object):    def findMaxConsecutiveOnes(self, nums):        """        :type nums: List[int]        :rtype: int        """        start,answer=0,0        while start<len(nums):            if not nums[start]:#如果是零                start+=1            else:                end=start+1                while end<len(nums)  and nums[end]:                    end+=1                answer=max(answer,end-start)                start=end+1        return answer

discuss有个更好的方法：
我们无需使用两个指针，只需要记录当前1的个数，如果遇到0，则把计数重置为0

class Solution(object):    def findMaxConsecutiveOnes(self, nums):        """        :type nums: List[int]        :rtype: int        """        count,answer=0,0        for x in nums:            if x==1:                count+=1                answer=max(answer,count)            else:                count=0        return answer