1570.A C

A C

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5288 Accepted Submission(s): 3406

Problem Description
Are you excited when you see the title “AC” ? If the answer is YES , AC it ;

You must learn these two combination formulas in the school . If you have forgotten it , see the picture.

Now I will give you n and m , and your task is to calculate the answer .

Input
In the first line , there is a integer T indicates the number of test cases.
Then T cases follows in the T lines.
Each case contains a character ‘A’ or ‘C’, two integers represent n and m. (1<=n,m<=10)

Output
For each case , if the character is ‘A’ , calculate A(m,n),and if the character is ‘C’ , calculate C(m,n).
And print the answer in a single line.

Sample Input
2
A 10 10
C 4 2

Sample Output
3628800
6

#include <stdio.h>#include <stdlib.h>#include <string.h>int f(int n){    int t=1,i;    if(n==1)    {        return 1;    }    for(i=n;i>0;i--)    {        t=t*i;    }    return t;}int main(){    int t,m,n,s;    char a;    scanf("%d",&t);    while(t--)    {        getchar();//代表回车，切记！！！        scanf("%c%d%d",&a,&n,&m);        if(a=='A')        {            s=f(n)/f(n-m);        }        else        {            s=f(n)/(f(m)*f(n-m));        }        printf("%d\n",s);    }    return 0;}