leetcode485 Max Consecutive Ones Java

Description

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.
Note:

The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000

解法1

遍历数组，找到最长的连续1。

public int findMaxConsecutivesOnes(int[] nums) {        int max = 0;        int count = 0;        for(int n : nums) {            if(n == 1) {                count ++;                if(count > max) max = count;            }else count = 0;        }        return max;    }

解法2

110111
^ count= 1

110111
. ^ count= 2

110111
. . ^ count= 0

110111
. . . ^ count= 1

110111
. . . . ^ count= 2

110111
. . . . . ^ count= 3

public int findMaxConsecutivesOnes(int[] nums) {        int max = 0;        int count = 0;        for(int n : nums) {            max = Math.max(max, count = n == 0 ? 0 : count+1);        }        return max;    }