HDU-1228-A + B（简单字符串处理)

来源：互联网发布：python 实现c4.5算法编辑：程序博客网时间：2024/04/29 06:20

//传送门：http://acm.hdu.edu.cn/showproblem.php?pid=1228   #include <queue>#include <functional>#include <stdio.h>#include <string.h>#include <iostream>#include <algorithm>#include <stack>#include <vector>#include <set>#include <map>#include <string>#include <cmath>#include <cstdlib>#include <ctime>#include <assert.h>using namespace std;#define N 15 string s;string tmp[N]={"zero","one","two","three","four","five","six","seven","eight","nine"};//利用字符串数组更方便操作int main(){   while(1){   int a=0;   while(cin>>s,s!="+"){           //以 "+" 分隔两个数字   for(int i=0;i<10;i++){   if(s==tmp[i]){   a=a*10+i; break;   }   }   }   int b=0;   while(cin>>s,s!="="){           //以 "=" 标志第二个数字输入结束   for(int i=0;i<10;i++){   if(s==tmp[i]){   b=b*10+i;   break;   }   }   }   if(a+b==0) break;   cout<<a+b<<endl;   }  return 0;}

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