python time datetime模块使用方法记录

来源:互联网 发布:各厂大数据平台 编辑:程序博客网 时间:2024/06/05 16:53
import timeimport datetime#time datetime使用方法备份print(time.clock())#   4.665275792443746e-07       返回处理器时间print(time.process_time())#   0.0780005print(time.time())#   1488616321.8451998          返回当前时间戳 <class 'float'>print(time.ctime())#   Sat Mar  4 16:34:51 2017    格式化返回系统时间   <class 'str'>print(time.ctime(887665))#   Sun Jan 11 14:34:25 1970print(time.ctime(time.time() - 60*60*24 ))#   Fri Mar  3 16:39:17 2017    输出前一天print(time.gmtime())#   time.struct_time(tm_year=2017, tm_mon=3, tm_mday=4, tm_hour=8, tm_min=41, tm_sec=32, tm_wday=5, tm_yday=63, tm_isdst=0)#   <class 'time.struct_time'>  格林尼治时间print(time.localtime())#   time.struct_time(tm_year=2017, tm_mon=3, tm_mday=4, tm_hour=16, tm_min=43, tm_sec=43, tm_wday=5, tm_yday=63, tm_isdst=0)#   <class 'time.struct_time'>  当地时间#   !!此时时间格式为struct_timeprint(time.mktime(time.localtime()))#   1488617178.0#   将struct_time时间转化为float格式的时间print(time.strftime("%Y-%m-%d %H:%M:%S",time.localtime(time.time() - 60*60*24)))#   2017-03-03 16:59:15#   将struct_time转化为字符串类型的时间#   首先:time.time() 为float格式 time.localtime() 的输入格式即为float,输出格式为struct_time#   time.strftime 又将struct_time 转化为字符串输出格式print(time.strptime('2017-03-03 16:59:15',"%Y-%m-%d %H:%M:%S"))#   time.struct_time(tm_year=2017, tm_mon=3, tm_mday=3, tm_hour=16, tm_min=59, tm_sec=15, tm_wday=4, tm_yday=62, tm_isdst=-1)#   与strftime相反,输入为字符串格式,按照格式对应的字段转化为struct_time格式#   '2017-03-03 16:59:15'与"%Y-%m-%d %H:%M:%S"是一一对应的。#   datetimeprint(datetime.date.today(),type(datetime.date.today()))#   2017-03-04     <class 'datetime.date'>#   当前日期print(datetime.date.fromtimestamp(time.time() - 60*60*24))#   2017-03-03#   将float格式的时间戳转化为<class 'datetime.date'>格式current_time = datetime.datetime.now()print(current_time)#   2017-03-04 17:20:41.851214      当前时间print(current_time.timetuple())#   time.struct_time(tm_year=2017, tm_mon=3, tm_mday=4, tm_hour=17, tm_min=21, tm_sec=42, tm_wday=5, tm_yday=63, tm_isdst=-1)#   将<class 'datetime.date'> 转化为 <class 'time.struct_time'>print(current_time.replace(2012))#   2012-03-04 17:29:53.446764#   替换时间并输出newtime = datetime.datetime.now() - datetime.timedelta(days=3)print(datetime.datetime.now(),'\t',newtime)#   2017-03-04 17:32:47.736732   2017-03-01 17:32:47.736732#   days=3 为3天时间  -号则表示3天前
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