HDU 2058 JAVA

来源：互联网发布：淘宝商城衣服女装编辑：程序博客网时间：2024/04/27 23:08

Problem Description
Given a sequence 1,2,3,……N, your job is to calculate all the possible sub-sequences that the sum of the sub-sequence is M.

Input
Input contains multiple test cases. each case contains two integers N, M( 1 <= N, M <= 1000000000).input ends with N = M = 0.

Output
For each test case, print all the possible sub-sequence that its sum is M.The format is show in the sample below.print a blank line after each test case.

Sample Input
20 10
50 30
0 0

Sample Output
[1,4]
[10,10]

[4,8]
[6,9]
[9,11]
[30,30]

import java.util.*;class Main {    public static void main(String args[]) {        Scanner cin = new Scanner(System.in);        while (cin.hasNext()) {            long n = cin.nextInt();            long m = cin.nextInt();            if (n == 0 && m == 0)                break;            long d = 0;            for (int i = (int) Math.sqrt(2 * m); i > 0; i--) {                d = m - (i + i * i) / 2;                if (d % i == 0)                    System.out.println("[" + (d / i + 1) + "," + (d / i + i)                            + "]");            }            System.out.println();        }    }}

0 0