PAT1002写出这个数

1. 写出这个数 (20)

读入一个自然数n，计算其各位数字之和，用汉语拼音写出和的每一位数字。

输入格式：每个测试输入包含1个测试用例，即给出自然数n的值。这里保证n小于10100。

输出格式：在一行内输出n的各位数字之和的每一位，拼音数字间有1 空格，但一行中最后一个拼音数字后没有空格。

输入样例：
1234567890987654321123456789
输出样例：
yi san wu

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#include "iostream"#include "string"using namespace std;int main(){    string str[10]{"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};    string s;    cin >> s;    int len = s.length();    int *a = new int [len];    int sum = 0;    for (int i = 0;i < len;i++)    {        a[i] = s[i] - '0';        sum = sum + a[i];     }    int *b = new int [len];    int j = 0;    if (sum == 0)    {        cout << str[0];    }    else    {        while (sum != 0)        {            b[j++] = sum % 10;            sum = sum / 10;        }        for (int i = j - 1;i >= 1;i--)        {            cout << str[b[i]] << ' ';        }        cout << str[b[0]] << endl;    }    delete [] a;    delete [] b;    return 0;}

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C代码：

#include<stdio.h>#include<string.h>char data[100]={0};int temp[3]={0};char data2[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};int main(int argc, char *argv[]){    int len=0,sum=0,i=0,j=0;    for(i=0;i<100 && (data[i]=getchar())!='\n';i++)    {  if(data[i]>47 && data[i]<58)     sum+=data[i]-48;    }    temp[0]=sum/100;    temp[1]=(sum-temp[0]*100)/10;    temp[2]=sum-temp[0]*100-temp[1]*10;    for(i=0,j=0;i<3;i++)    {    if(temp[i]==0 && j==0 && i!=2) continue;    else     {    j=1;    printf("%s",data2[temp[i]]);    }    if(i!=2)        printf(" ");    else        printf("\n");    } return 0;}

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