PAT 1125

第二题很多人都说是赫夫曼树,我就排了个序就过了,之后推敲了一下这个逻辑是可行的,当然赫夫曼树也是正解,有兴趣的同学可以用赫夫曼树做一下

#include<iostream>#include<vector>#include<string>#include<algorithm>using namespace std;int main(){int n, i;double s[10005], len = 0;scanf("%d", &n);for (i = 0; i < n; i++) {scanf("%lf", &s[i]);}sort(s, s + n);len = s[0];for (i = 1; i < n; i++) {len = len / 2 + s[i] / 2;}int l = (int)(len);if (l <= len) {printf("%d\n", l);}else {printf("%d\n", l - 1);}return 0;}