找到两个数的差为一个特定数

Given an integer 'k' and an sorted array A (can consist of both +ve/-ve nos), output 2 integers from A such that a-b=k.

void fun(vector<int> &a, int key){int n = a.size();if (n <= 1){return;}key = abs(key);int p = 1;int q = 0;while (q < p && p < n){if (a[p] - a[q] == key){cout << a[p] << " " << a[q] << endl;return;}else if (a[p] - a[q] > key){q++;}else{p++;}}}