The Largest Generation

题目描述

A family hierarchy is usually presented by a pedigree tree where all the nodes on the same level belong to the same generation.  Your task is to find the generation with the largest population.

输入描述:

Each input file contains one test case.  Each case starts with two positive integers N (<100) which is the total number of family members in the tree (and hence assume that all the members are numbered from 01 to N), and M (<N) which is the number of family members who have children.  Then M lines follow, each contains the information of a family member in the following format:ID K ID[1] ID[2] ... ID[K]where ID is a two-digit number representing a family member, K (>0) is the number of his/her children, followed by a sequence of two-digit ID's of his/her children. For the sake of simplicity, let us fix the root ID to be 01.  All the numbers in a line are separated by a space.

输出描述:

For each test case, print in one line the largest population number and the level of the corresponding generation.  It is assumed that such a generation is unique, and the root level is defined to be 1.

输入例子:

23 1321 1 2301 4 03 02 04 0503 3 06 07 0806 2 12 1313 1 2108 2 15 1602 2 09 1011 2 19 2017 1 2205 1 1107 1 1409 1 1710 1 18

输出例子:

9 4

代码：

#include"iostream"
#include "cstring"
#include "cmath"
#include "vector"
#include<iomanip>
using namespace std;


struct Person
{
int Generation = 0;
};
Person people[101];
vector<int> Generation[101];


void SetLength(int index, int length)
{
people[index].Generation = length;
if (Generation[index].size() != 0)
for (int i = 0; i < Generation[index].size(); i++)
SetLength(Generation[index][i], length + 1);
}


int main()
{
int N, M;
cin >> N >> M;
for (int i = 0; i < M; i++)
{
int k, index;
cin >> index >> k;
for (int j = 0; j < k; j++)
{
int temp;
cin >> temp;
Generation[index].push_back(temp);
}
}
SetLength(1, 1);
int count[101];
memset(count, 0, sizeof(count));
for (int i = 1; i <= N; i++)
{
count[people[i].Generation]++;
}
int max = -1, index = 0;
for (int i = 1; i <= N; i++)
{
if (count[i] > max)
{
max = count[i];
index = i;
}
}
cout << max << " " << index;
}

思路：

采用哈希表，哈希函数为原值。