简单的一个用定时器控制的流水灯c程序

用定时器以间隔500MS在6位数码管上依次显示0、1、2、3….C、D、E、F，重复。

#include<reg52.h>
typedef unsigned int u8;
typedef unsigned char u16;
u8 code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};
u8 code weixuan[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf};
sbit duan=P2^6;
sbit wei=P2^7;
u8 i=0,j=0;
void time0()
{
    TH0=(65536-5000)/256;
 TL0=(65536-5000)%256;
 EA=1;
 ET0=1;
 TR0=1;
 while(1);
}

void main() 
{
  TMOD=0x01;
  time0();
}

void time1() interrupt 1
{ 
 wei=0;
 P0=weixuan[(i++)%16];
   wei=1;
  duan=0;
   P0=table[(j++)%6];
   duan=1;
   TH0=(65536-5000)/256;
 TL0=(65536-5000)%256;
}