Python时间操作--获取微秒级别的时间差

Python中有两个模块可以完成时间操作：time和datetime

相比较而言datetime更强大

以下分别是两个模块的具体信息

>>> dir(time)['__doc__', '__name__', '__package__', 'accept2dyear', 'altzone', 'asctime', 'clock', 'ctime', 'daylight', 'gmtime', 'localtime', 'mktime', 'sleep', 'strftime', 'strptime', 'struct_time', 'time', 'timezone', 'tzname', 'tzset']>>> dir(datetime.datetime)['__add__', '__class__', '__delattr__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__ne__', '__new__', '__radd__', '__reduce__', '__reduce_ex__', '__repr__', '__rsub__', '__setattr__', '__sizeof__', '__str__', '__sub__', '__subclasshook__', 'astimezone', 'combine', 'ctime', 'date', 'day', 'dst', 'fromordinal', 'fromtimestamp', 'hour', 'isocalendar', 'isoformat', 'isoweekday', 'max', 'microsecond', 'min', 'minute', 'month', 'now', 'replace', 'resolution', 'second', 'strftime', 'strptime', 'time', 'timetuple', 'timetz', 'today', 'toordinal', 'tzinfo', 'tzname', 'utcfromtimestamp', 'utcnow', 'utcoffset', 'utctimetuple', 'weekday', 'year']

如果要获取微秒级别的时间差，可以利用以下代码

import datetimebegin = datetime.datetime.now()end = datetime.datetime.now()k = end - begin

再看下k的属性和方法

>>> dir(k)['__abs__', '__add__', '__class__', '__delattr__', '__div__', '__doc__', '__eq__', '__floordiv__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__mul__', '__ne__', '__neg__', '__new__', '__nonzero__', '__pos__', '__radd__', '__rdiv__', '__reduce__', '__reduce_ex__', '__repr__', '__rfloordiv__', '__rmul__', '__rsub__', '__setattr__', '__sizeof__', '__str__', '__sub__', '__subclasshook__', 'days', 'max', 'microseconds', 'min', 'resolution', 'seconds', 'total_seconds']

k为datetime.timedelta类型，以上是timedelta的所有的属性和函数
利用以下代码可以获取以秒为单位的时间差，小数点后6位为微秒。

k.total_seconds()

>>> k.total_seconds()2303.277522