[LeetCode]54. Spiral Matrix
来源:互联网 发布:unity3d 麻将开发 编辑:程序博客网 时间:2024/06/16 22:06
https://leetcode.com/problems/spiral-matrix/?tab=Description
旋转遍历二维数组
数组可能是[[1,2]]这种case,所以要保证rowBeg <= rowEnd && colBeg <= colEnd
public class Solution { public List<Integer> spiralOrder(int[][] matrix) { List<Integer> res = new ArrayList<Integer>(); if (matrix.length == 0) { return res; } int rowBegin = 0; int rowEnd = matrix.length-1; int colBegin = 0; int colEnd = matrix[0].length - 1; while (rowBegin <= rowEnd && colBegin <= colEnd) { // Traverse Right for (int j = colBegin; j <= colEnd; j ++) { res.add(matrix[rowBegin][j]); } rowBegin++; // Traverse Down for (int j = rowBegin; j <= rowEnd; j ++) { res.add(matrix[j][colEnd]); } colEnd--; if (rowBegin <= rowEnd) { // Traverse Left for (int j = colEnd; j >= colBegin; j --) { res.add(matrix[rowEnd][j]); } } rowEnd--; if (colBegin <= colEnd) { // Traver Up for (int j = rowEnd; j >= rowBegin; j --) { res.add(matrix[j][colBegin]); } } colBegin ++; } return res; }}
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