利用互斥锁+条件变量进行奇偶交替打印

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线程1打印奇数,线程2打印偶数

#include<stdio.h>#include<unistd.h>#include<pthread.h>#define MAX_COUNT 10pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;pthread_cond_t cond = PTHREAD_COND_INITIALIZER;int count = 1;//1 3 5 7 9void* fun1(void *arg){    pthread_mutex_lock(&mutex);    while(count <= MAX_COUNT)    {        if(count % 2 == 1)        {            printf("This is threadfun1 %d\n", count);            count++;            pthread_cond_signal(&cond);        }        else            pthread_cond_wait(&cond, &mutex);        //sleep(1);    }    pthread_mutex_unlock(&mutex);}//2 4 6 8 10void* fun2(void *arg){    pthread_mutex_lock(&mutex);    while(count <= MAX_COUNT)    {        if(count % 2 == 0)        {            printf("This is threadfun2 %d\n", count);           count++;            pthread_cond_signal(&cond);        }        else            pthread_cond_wait(&cond, &mutex);    }    pthread_mutex_unlock(&mutex);}int main(int argc, char const* argv[]){    pthread_t tid[2];    pthread_create(&tid[0], NULL, fun1, NULL);    // sleep(1);    pthread_create(&tid[1], NULL, fun2, NULL);    for(int i=0; i<2; ++i)    {        pthread_join(tid[i],NULL);    }    return 0;}

结果
这里写图片描述

1 0