【zzuli】九进制转化为十进制

E - E

Crawling in process...Crawling failedTime Limit:1000MS    Memory Limit:65536KB     64bit IO Format:%I64d & %I64u

SubmitStatus

Description

You are given a car odometer which displays the miles traveled as an integer. The odometer has a defect, however: it proceeds from the digit 3 to the digit 5, always skipping over the digit 4. This defect shows up in all positions (the one's, the ten's, the hundred's, etc.). For example, if the odometer displays 15339 and the car travels one mile, odometer reading changes to 15350 (instead of 15340).

Input

Each line of input contains a positive integer in the range 1..999999999 which represents an odometer reading. (Leading zeros will not appear in the input.) The end of input is indicated by a line containing a single 0. You may assume that no odometer reading will contain the digit 4.

Output

Each line of input will produce exactly one line of output, which will contain: the odometer reading from the input, a colon, one blank space, and the actual number of miles traveled by the car.

Sample Input

131520032005239250139915009999990

Sample Output

13: 1215: 132003: 14612005: 1462239: 197250: 1981399: 10521500: 1053999999: 531440    （85)9=((0*9)+8)*9+5)10=(77)10

#include<cstdio>#include<cstring>#include<algorithm>using namespace std;int main(){char s[100];int num[100];while(~scanf("%s",s)&&s[0]!='0'){int l=strlen(s);for(int i=0;i<l;i++){num[i]=s[i]-'0';if(num[i]>=5) num[i]-=1;//因为没有4 }int sum=0;for(int i=0;i<l;i++) sum=sum*9+num[i]; printf("%s: %d\n",s,sum);}return 0;}