JAVA

来源:互联网 发布:查看ftp使用的端口 编辑:程序博客网 时间:2024/05/22 15:05

JAVA老师给我们留了一个课后作业,要求我们通过搜索JDK用尽可能多的方法删除String类中的指定字符,我只想到了 11 种方法,如果有不足或者遗漏希望读者能够不吝赐教。

第一种方法 – 通过循环从前往后遍历,如果不是要删除的字符则加到处理后的字符串中,代码如下:

    public String deleteCharString0(String sourceString, char chElemData) {        String deleteString = "";        for (int i = 0; i < sourceString.length(); i++) {            if (sourceString.charAt(i) != chElemData) {                deleteString += sourceString.charAt(i);            }        }        return deleteString;    }

第二种方法 — 通过循环确定要删除字符的位置索引,然后通过分割字符串的形式,将子字符串拼接,注意最后一段子字符串和源字符串中没有要删除字符的情况,代码如下:

    public String deleteCharString1(String sourceString, char chElemData) {        String deleteString = "";        int iIndex = 0;        for (int i = 0; i < sourceString.length(); i++) {            if (sourceString.charAt(i) == chElemData) {                if (i > 0) {                    deleteString += sourceString.substring(iIndex, i);                }                iIndex = i + 1;            }        }        if (iIndex <= sourceString.length()) {            deleteString += sourceString.substring(iIndex, sourceString.length());        }        return deleteString;    }

第三种方法 — 原理同上,只不过查找要删除字符位置采用String类中的函数执行,效率不如上面的高,代码如下:

    public String deleteCharString2(String sourceString, char chElemData) {        String deleteString = "";        int iIndex = 0;        int tmpCount = 0;        do {            tmpCount = sourceString.indexOf(chElemData, iIndex);            if (tmpCount > 0) {                deleteString += sourceString.substring(iIndex, tmpCount);            }            if (tmpCount != -1) {                iIndex = tmpCount + 1;            }        } while (tmpCount != -1);        if (iIndex <= sourceString.length()) {            deleteString += sourceString.substring(iIndex, sourceString.length());        }        return deleteString;    }

第四种方法 — 原理与上方基本一致,只不过这次采用倒序方式,这里的坑就更多了,一定要注意索引的取值范围和是否合法,代码如下:

    public String deleteCharString3(String sourceString, char chElemData) {        String deleteString = "";        int iIndex = sourceString.length();        int tmpCount = 0;        do {            tmpCount = sourceString.lastIndexOf(chElemData, iIndex - 1);            if (tmpCount < sourceString.length() && tmpCount >= 0) {                deleteString = sourceString.substring(tmpCount + 1, iIndex) + deleteString;            }            if (tmpCount != -1) {                iIndex = tmpCount;            }        } while (tmpCount != -1);        if (iIndex >= 0) {            deleteString = sourceString.substring(0, iIndex) + deleteString;        }        return deleteString;    }

第五种方法 — 通过采用正则的方式和replaceAll函数,本种方法要注意特殊字符,例如正则中的 “.”字符,需要对特殊字符进行转义,代码如下:

    public String deleteCharString4(String sourceString, char chElemData) {        String deleteString = "";        final String strTable = "|^$*+?.(){}\\";        String tmpRegex = "[";         for (int i = 0; i < strTable.length(); i++) {            if (strTable.charAt(i) == chElemData) {                tmpRegex += "\\";                break;            }        }        tmpRegex += chElemData + "]";        deleteString = sourceString.replaceAll(tmpRegex, "");        return deleteString;    }

第六种方法 — 采用正则的方式将字符串分割成几个子字符串,再将子字符串进行拼接,代码如下:

    public String deleteCharString5(String sourceString, char chElemData) {        String deleteString = "";        final String strTable = "|^$*+?.(){}\\";        String tmpRegex = "[";         for (int i = 0; i < strTable.length(); i++) {            if (strTable.charAt(i) == chElemData) {                tmpRegex += "\\";                break;            }        }        tmpRegex += chElemData + "]";        String[] tmpStringArray = sourceString.split(tmpRegex);        for (int i = 0; i < tmpStringArray.length; i++) {            deleteString += tmpStringArray[i];        }        return deleteString;    }

第七种方法 — 将字符编程可读序列,在通过 String 类中的方法替换,代码如下:

    public String deleteCharString6(String sourceString, char chElemData) {        String tmpString = "";        tmpString += chElemData;        tmpString.subSequence(0, 0);        String deleteString = "";        deleteString = sourceString.replace(tmpString, deleteString.subSequence(0, 0));        return deleteString;    }

第八种方法 — 把原字符串转化为字符数组,然后原理与直接插入排序原理类似,代码如下:

    public String deleteCharString7(String sourceString, char chElemData) {        String deleteString = "";        char[] Bytes = sourceString.toCharArray();        int iSize = Bytes.length;        for (int i = Bytes.length - 1; i >= 0; i--) {            if (Bytes[i] == chElemData) {                for (int j = i; j < iSize - 1; j++) {                    Bytes[j] = Bytes[j + 1];                }                iSize--;            }        }        for (int i = 0; i < iSize; i++) {            deleteString += Bytes[i];        }        return deleteString;    }

第九种方法 — 原理与 第一种方法 类似,本次采用 stringBuffer 类中的 append 方法进行操作,我认为效率应该高于第一种。

    public String deleteCharString8(String sourceString, char chElemData) {        StringBuffer stringBuffer = new StringBuffer("");        for (int i = 0; i < sourceString.length(); i++) {            if (sourceString.charAt(i) != chElemData) {                stringBuffer.append(sourceString.charAt(i));            }        }        return stringBuffer.toString();    }

第十种方法 — 采用 stringBuffer 类中的 replace and indexOf 方法(^_^ 故意凑方法),代码如下:

    public String deleteCharString9(String sourceString, char chElemData) {        String tmpString = "";        tmpString += chElemData;        StringBuffer stringBuffer = new StringBuffer(sourceString);        int iFlag = -1;        do {            iFlag = stringBuffer.indexOf(tmpString);            if (iFlag != -1) {                stringBuffer = stringBuffer.replace(iFlag, iFlag + 1, "");            }        } while (iFlag != -1);        return stringBuffer.toString();    }

第十一种方法 — 采用 stringBuffer 类中的 deleteCharAt 和 indexOf 直接删除

    public String deleteCharString10(String sourceString, char chElemData) {        String tmpString = "";        tmpString += chElemData;        StringBuffer stringBuffer = new StringBuffer(sourceString);        int iFlag = -1;        do {            iFlag = stringBuffer.indexOf(tmpString);            if (iFlag != -1) {                stringBuffer.deleteCharAt(iFlag);            }        } while (iFlag != -1);        return stringBuffer.toString();    }

程序运行截图:
这里写图片描述

7 0
原创粉丝点击